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I have to strip anything that isn't a letter between a-z (lowercase only) out of a sentence. I wrote this [code=python]def breakPhrase(string): string=string.lower() for character in string: if ord(character) < 97 or ord(character) > 122: string=string.strip(character) return string[/code] and it works, but only if theres only one punctuation or non …
I'm getting an unresolved symbols linking error with this code, the cpp files compile successfully separately, I just can't build the solution and run it. any ideas? header.h [code=c++] #include <iostream> #include <string> using std::string; using namespace std; class Double { private: double dub; char str[50]; public: Double(); Double(char s[50]); …
This is my current coding, in my header file [code=c++] #ifndef _ADDRESSBOOK #define _ADDRESSBOOK const int MAXADDRESS = 25; struct PERSON { char fName[25]; char lname[25]; char Address[100]; }; class addressBook { private: PERSON people[10]; public: addressBook(); addressBook(char *fName, char*lname, char *add); addressBook(PERSON a); addressBook(PERSON init[], int count); bool addPerson(const …
can someone show me some code to convert rankine temperature to kelvin? rankine is in the same scale as fahrenheit, but it starts at absolute zero. so 0R = -459.67F, heres is what I have convert to kelvin [code=python] def __init__(self, value=0): Fah=value-459.69 Cel=(Fah-32)*5/9.0 value=Cel-273.15 Temperature.__init__(self, value) [/code] convert back …
That looks like you have the general idea, you just need to format the code right. First I would write the menu using print statements, and then get the answer with an raw_input statement [code=python]print 'for small press "a"' print 'for medium press "b"' print 'for large press "c"' choice=raw_input()[/code] …
Hi guys, I'm learning python right now, and I'm having a little trouble with one of my assignments. I have to write a program that will take a word and "encrypt" it. an example, if the letter is 'a' then it should get converted to 'b'. I have the code …
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