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Member Avatar for ecoloney

Using VS 2013 Express for Desktop. C#. Winblows 8.1 I have a clever program for writing/printing/storing invoices and quotes. One function is to print to PDF using CutePDF Writer. All is well except the dialog to name and save the file doesn't pop up to the front unless I click …

Member Avatar for Fenrir()
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153
Member Avatar for templersstorms

Have you looked at: [code] DataGridView dgvMyName = new DataGridView(); [/code] You need to recognize a click or other event inside of the DGV such as when you release the mouse button: [code] dgvMyName_MouseUp (object sender, MouseEventArgs e) { // get the current row int iSelectedRow; iSelectedRow = dgvMyName.CurrentRow.Index; // …

Member Avatar for templersstorms
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108
Member Avatar for xpartmgr

Looking at your data, it appears each value you want is 'delimited' by " " (quote-space-quote). Have you tried using String.Split to separate the text data from each line? I don't know about reading the int but if every line is in succession, that should be easy to substitute the …

Member Avatar for ecoloney
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113
Member Avatar for ecoloney

Friends, I have some menus. I click on a menu to perform a function. It "closes" the dropdown but the screen behind the dropdown does NOT refresh until after the code for the menu item code finishes executing (several seconds). How do I get the screen to refresh right away? …

Member Avatar for LevyDee
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Member Avatar for ecoloney

Friends, My main form is located toward the right side of my screen so as not to cover up other open programs. I wish to locate MessageBoxes in relation to my main form (typically centered over my main form) instead of a relation to the screen. How do I do …

Member Avatar for Nemo_NIIT
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105
Member Avatar for ecoloney

I wish to create a class of text boxes (I could use an array but I'd rather use a class). How do I assign the class a parent (much like textBox.Parent = someForm, etc.)? Thanks,

Member Avatar for Geekitygeek
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113
Member Avatar for UniqueMan

I suspect that request may not be worded correctly. 1 foot = 12 inches. 1 inch = 2.54 cm 12 inches = 12 * 2.54 cm = 30.48 cm Conversely, 30.48 cm = 1 foot. Therefore 1 cm = 1 foot/30.48 which means 1 cm = .0328083 feet.

Member Avatar for UniqueMan
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314
Member Avatar for ruelk

I've encountered a similar challenge, myself, and have seen several "fixes" on the web that were far beyond my understanding. Here's what I did: 1. declare globally: your second form and the controls it uses, such as a string, text box, etc. 2. Put a button on your first form …

Member Avatar for ecoloney
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Member Avatar for ecoloney

Friends, I have an array of TEdits. They all use the same On Key Down method. How can I determine (from within my On Key Down method) which TEdit called the method ? Thanks,

Member Avatar for John A
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138

The End.